练习:构建器类型
在此示例中,我们将实现一个拥有全部数据所有权的复杂数据类型。我们将使用 “构建器模式”来支持逐步构建新值,通过便捷函数来实现。
填补缺失的内容。
#[derive(Debug)]
enum Language {
Rust,
Java,
Perl,
}
#[derive(Clone, Debug)]
struct Dependency {
name: String,
version_expression: String,
}
/// A representation of a software package.
#[derive(Debug)]
struct Package {
name: String,
version: String,
authors: Vec<String>,
dependencies: Vec<Dependency>,
language: Option<Language>,
}
impl Package {
/// Return a representation of this package as a dependency, for use in
/// building other packages.
fn as_dependency(&self) -> Dependency {
todo!("1")
}
}
/// A builder for a Package. Use `build()` to create the `Package` itself.
struct PackageBuilder(Package);
impl PackageBuilder {
fn new(name: impl Into<String>) -> Self {
todo!("2")
}
/// Set the package version.
fn version(mut self, version: impl Into<String>) -> Self {
self.0.version = version.into();
self
}
/// Set the package authors.
fn authors(mut self, authors: Vec<String>) -> Self {
todo!("3")
}
/// Add an additional dependency.
fn dependency(mut self, dependency: Dependency) -> Self {
todo!("4")
}
/// Set the language. If not set, language defaults to None.
fn language(mut self, language: Language) -> Self {
todo!("5")
}
fn build(self) -> Package {
self.0
}
}
fn main() {
let base64 = PackageBuilder::new("base64").version("0.13").build();
println!("base64: {base64:?}");
let log =
PackageBuilder::new("log").version("0.4").language(Language::Rust).build();
println!("log: {log:?}");
let serde = PackageBuilder::new("serde")
.authors(vec!["djmitche".into()])
.version(String::from("4.0"))
.dependency(base64.as_dependency())
.dependency(log.as_dependency())
.build();
println!("serde: {serde:?}");
}