Building a non-persistent instance

In order to create instances of defined classes just do as follows. You might recognize the syntax if you coded Ruby in the past. Using the build-method will return an unsaved object, which you explicitly have to save.

  1. const project = Project.build({
  2.   title: 'my awesome project',
  3.   description: 'woot woot. this will make me a rich man'
  4. })
  6. const task = Task.build({
  7.   title: 'specify the project idea',
  8.   description: 'bla',
  9.   deadline: new Date()
  10. })

Built instances will automatically get default values when they were defined:

  1. // first define the model
  2. class Task extends Model {}
  3. Task.init({
  4.   title: Sequelize.STRING,
  5.   rating: { type: Sequelize.TINYINT, defaultValue: 3 }
  6. }, { sequelize, modelName: 'task' });
  8. // now instantiate an object
  9. const task = Task.build({title: 'very important task'})
  11. task.title  // ==> 'very important task'
  12. task.rating // ==> 3

To get it stored in the database, use the save-method and catch the events … if needed:

  1. project.save().then(() => {
  2.   // my nice callback stuff
  3. })
  5. task.save().catch(error => {
  6.   // mhhh, wth!
  7. })
  9. // you can also build, save and access the object with chaining:
  10. Task
  11.   .build({ title: 'foo', description: 'bar', deadline: new Date() })
  12.   .save()
  13.   .then(anotherTask => {
  14.     // you can now access the currently saved task with the variable anotherTask... nice!
  15.   })
  16.   .catch(error => {
  17.     // Ooops, do some error-handling
  18.   })