Upload files
Single file
References issue #774 and detail example code.
func main() {
router := gin.Default()
// Set a lower memory limit for multipart forms (default is 32 MiB)
// router.MaxMultipartMemory = 8 << 20 // 8 MiB
router.POST("/upload", func(c *gin.Context) {
// single file
file, _ := c.FormFile("file")
log.Println(file.Filename)
// Upload the file to specific dst.
// c.SaveUploadedFile(file, dst)
c.String(http.StatusOK, fmt.Sprintf("'%s' uploaded!", file.Filename))
})
router.Run(":8080")
}
How to curl
:
curl -X POST http://localhost:8080/upload \
-F "file=@/Users/appleboy/test.zip" \
-H "Content-Type: multipart/form-data"
Multiple files
See the detail example code.
func main() {
router := gin.Default()
// Set a lower memory limit for multipart forms (default is 32 MiB)
// router.MaxMultipartMemory = 8 << 20 // 8 MiB
router.POST("/upload", func(c *gin.Context) {
// Multipart form
form, _ := c.MultipartForm()
files := form.File["upload[]"]
for _, file := range files {
log.Println(file.Filename)
// Upload the file to specific dst.
// c.SaveUploadedFile(file, dst)
}
c.String(http.StatusOK, fmt.Sprintf("%d files uploaded!", len(files)))
})
router.Run(":8080")
}
How to curl
:
curl -X POST http://localhost:8080/upload \
-F "upload[]=@/Users/appleboy/test1.zip" \
-F "upload[]=@/Users/appleboy/test2.zip" \
-H "Content-Type: multipart/form-data"