Happy Number
Tags: Hash Table, Math, Easy
Question
- leetcode: Happy Number
- lintcode: Happy Number
Problem Statement
Write an algorithm to determine if a number is “happy”.
A happy number is a number defined by the following process: Starting with any
positive integer, replace the number by the sum of the squares of its digits,
and repeat the process until the number equals 1 (where it will stay), or it
loops endlessly in a cycle which does not include 1. Those numbers for which
this process ends in 1 are happy numbers.
Example: 19 is a happy number
- $$1^2 + 9^2 = 82$$
- $$8^2 + 2^2 = 68$$
- $$6^2 + 8^2 = 100$$
- $$1^2 + 0^2 + 0^2 = 1$$
Credits:
Special thanks to @mithmatt and
@ts for adding this problem and
creating all test cases.
题解
根据指定运算规则判断输入整数是否为『happy number』,容易推断得知最终要么能求得1,要么为环形队列不断循环。
第一种情况容易判断,第二种情况即判断得到的数是否为环形队列,也就是说是否重复出现,这种场景使用哈希表轻易解决。
Java
public class Solution {
public boolean isHappy(int n) {
if (n < 0) return false;
Set<Integer> set = new HashSet<Integer>();
set.add(n);
while (n != 1) {
n = digitsSquareSum(n);
if (n == 1) {
return true;
} else if (set.contains(n)) {
return false;
} else {
set.add(n);
}
}
return true;
}
private int digitsSquareSum(int n) {
int sum = 0;
for (; n > 0; n /= 10) {
sum += (n % 10) * (n % 10);
}
return sum;
}
}
源码分析
辅助方法计算数字平方和。
复杂度分析
有限迭代次数一定终止,时间和空间复杂度均为 O(1).