栈
From Wikipedia, a stack is an abstract data type that serves as a collection of elements, with two main principal operations, Push
and Pop
.
Properties
- Push O(1)
- Pop head.data O(1) tail.data O(n)
- Peek O(1)
// the public struct can hide the implementation detail
pub struct Stack<T> {
head: Link<T>,
}
type Link<T> = Option<Box<Node<T>>>;
struct Node<T> {
elem: T,
next: Link<T>,
}
impl<T> Stack<T> {
// Self is an alias for Stack
// We implement associated function name new for single-linked-list
pub fn new() -> Self {
// for new function we need to return a new instance
Self {
// we refer to variants of an enum using :: the namespacing operator
head: None,
} // we need to return the variant, so there without the ;
}
// As we know the primary forms that self can take: self, &mut self and &self, push will change the linked list
// so we need &mut
// The push method which the signature's first parameter is self
pub fn push(&mut self, elem: T) {
let new_node = Box::new(Node {
elem,
next: self.head.take(),
});
// don't forget replace the head with new node for stack
self.head = Some(new_node);
}
///
/// In pop function, we trying to:
/// * check if the list is empty, so we use enum Option<T>, it can either be Some(T) or None
/// * if it's empty, return None
/// * if it's not empty
/// * remove the head of the list
/// * remove its elem
/// * replace the list's head with its next
/// * return Some(elem), as the situation if need
///
/// so, we need to remove the head, and return the value of the head
pub fn pop(&mut self) -> Result<T, &str> {
match self.head.take() {
None => Err("Stack is empty"),
Some(node) => {
self.head = node.next;
Ok(node.elem)
}
}
}
pub fn is_empty(&self) -> bool {
// Returns true if the option is a [None] value.
self.head.is_none()
}
pub fn peek(&self) -> Option<&T> {
// Converts from &Option<T> to Option<&T>.
match self.head.as_ref() {
None => None,
Some(node) => Some(&node.elem),
}
}
pub fn peek_mut(&mut self) -> Option<&mut T> {
match self.head.as_mut() {
None => None,
Some(node) => Some(&mut node.elem),
}
}
pub fn into_iter_for_stack(self) -> IntoIter<T> {
IntoIter(self)
}
pub fn iter(&self) -> Iter<'_, T> {
Iter {
next: self.head.as_deref(),
}
}
// '_ is the "explicitly elided lifetime" syntax of Rust
pub fn iter_mut(&mut self) -> IterMut<'_, T> {
IterMut {
next: self.head.as_deref_mut(),
}
}
}
impl<T> Default for Stack<T> {
fn default() -> Self {
Self::new()
}
}
/// The drop method of singly linked list. There's a question that do we need to worry about cleaning up our list?
/// As we all know the ownership and borrow mechanism, so we know the type will clean automatically after it goes out the scope,
/// this implement by the Rust compiler automatically did which mean add trait `drop` for the automatically.
///
/// So, the complier will implements Drop for `List->Link->Box<Node> ->Node` automatically and tail recursive to clean the elements
/// one by one. And we know the recursive will stop at Box<Node>
/// https://rust-unofficial.github.io/too-many-lists/first-drop.html
///
/// As we know we can't drop the contents of the Box after deallocating, so we need to manually write the iterative drop
impl<T> Drop for Stack<T> {
fn drop(&mut self) {
let mut cur_link = self.head.take();
while let Some(mut boxed_node) = cur_link {
cur_link = boxed_node.next.take();
// boxed_node goes out of scope and gets dropped here;
// but its Node's `next` field has been set to None
// so no unbound recursion occurs.
}
}
}
/// Rust has nothing like a yield statement, and there's actually 3 different kinds of iterator should to implement
// Collections are iterated in Rust using the Iterator trait, we define a struct implement Iterator
pub struct IntoIter<T>(Stack<T>);
impl<T> Iterator for IntoIter<T> {
// This is declaring that every implementation of iterator has an associated type called Item
type Item = T;
// the reason iterator yield Option<self::Item> is because the interface coalesces the `has_next` and `get_next` concepts
fn next(&mut self) -> Option<Self::Item> {
self.0.pop().ok()
}
}
pub struct Iter<'a, T> {
next: Option<&'a Node<T>>,
}
impl<'a, T> Iterator for Iter<'a, T> {
type Item = &'a T;
fn next(&mut self) -> Option<Self::Item> {
self.next.map(|node| {
// as_deref: Converts from Option<T> (or &Option<T>) to Option<&T::Target>.
self.next = node.next.as_deref();
&node.elem
})
}
}
pub struct IterMut<'a, T> {
next: Option<&'a mut Node<T>>,
}
impl<'a, T> Iterator for IterMut<'a, T> {
type Item = &'a mut T;
fn next(&mut self) -> Option<Self::Item> {
// we add take() here due to &mut self isn't Copy(& and Option<&> is Copy)
self.next.take().map(|node| {
self.next = node.next.as_deref_mut();
&mut node.elem
})
}
}
#[cfg(test)]
mod test_stack {
use super::*;
#[test]
fn basics() {
let mut list = Stack::new();
assert_eq!(list.pop(), Err("Stack is empty"));
list.push(1);
list.push(2);
list.push(3);
assert_eq!(list.pop(), Ok(3));
assert_eq!(list.pop(), Ok(2));
list.push(4);
list.push(5);
assert_eq!(list.is_empty(), false);
assert_eq!(list.pop(), Ok(5));
assert_eq!(list.pop(), Ok(4));
assert_eq!(list.pop(), Ok(1));
assert_eq!(list.pop(), Err("Stack is empty"));
assert_eq!(list.is_empty(), true);
}
#[test]
fn peek() {
let mut list = Stack::new();
assert_eq!(list.peek(), None);
list.push(1);
list.push(2);
list.push(3);
assert_eq!(list.peek(), Some(&3));
assert_eq!(list.peek_mut(), Some(&mut 3));
match list.peek_mut() {
None => None,
Some(value) => Some(*value = 42),
};
assert_eq!(list.peek(), Some(&42));
assert_eq!(list.pop(), Ok(42));
}
#[test]
fn into_iter() {
let mut list = Stack::new();
list.push(1);
list.push(2);
list.push(3);
let mut iter = list.into_iter_for_stack();
assert_eq!(iter.next(), Some(3));
assert_eq!(iter.next(), Some(2));
assert_eq!(iter.next(), Some(1));
assert_eq!(iter.next(), None);
}
#[test]
fn iter() {
let mut list = Stack::new();
list.push(1);
list.push(2);
list.push(3);
let mut iter = list.iter();
assert_eq!(iter.next(), Some(&3));
assert_eq!(iter.next(), Some(&2));
assert_eq!(iter.next(), Some(&1));
}
#[test]
fn iter_mut() {
let mut list = Stack::new();
list.push(1);
list.push(2);
list.push(3);
let mut iter = list.iter_mut();
assert_eq!(iter.next(), Some(&mut 3));
assert_eq!(iter.next(), Some(&mut 2));
assert_eq!(iter.next(), Some(&mut 1));
}
}
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