Type Guard
Type Guards allow you to narrow down the type of an object within a conditional block.
typeof
TypeScript is aware of the usage of the JavaScript instanceof
and typeof
operators. If you use these in a conditional block, TypeScript will understand the type of the variable to be different within that conditional block. Here is a quick example where TypeScript realizes that a particular function does not exist on string
and points out what was probably a user typo:
function doSomething(x: number | string) {
if (typeof x === 'string') { // Within the block TypeScript knows that `x` must be a string
console.log(x.subtr(1)); // Error, 'subtr' does not exist on `string`
console.log(x.substr(1)); // OK
}
x.substr(1); // Error: There is no guarantee that `x` is a `string`
}
instanceof
Here is an example with a class and instanceof
:
class Foo {
foo = 123;
common = '123';
}
class Bar {
bar = 123;
common = '123';
}
function doStuff(arg: Foo | Bar) {
if (arg instanceof Foo) {
console.log(arg.foo); // OK
console.log(arg.bar); // Error!
}
if (arg instanceof Bar) {
console.log(arg.foo); // Error!
console.log(arg.bar); // OK
}
console.log(arg.common); // OK
console.log(arg.foo); // Error!
console.log(arg.bar); // Error!
}
doStuff(new Foo());
doStuff(new Bar());
TypeScript even understands else
so when an if
narrows out one type it knows that within the else it’s definitely not that type. Here is an example:
class Foo {
foo = 123;
}
class Bar {
bar = 123;
}
function doStuff(arg: Foo | Bar) {
if (arg instanceof Foo) {
console.log(arg.foo); // OK
console.log(arg.bar); // Error!
}
else { // MUST BE Bar!
console.log(arg.foo); // Error!
console.log(arg.bar); // OK
}
}
doStuff(new Foo());
doStuff(new Bar());
in
The in
operator does a safe check for the existance of a property on an object and can be used as a type guard. E.g.
interface A {
x: number;
}
interface B {
y: string;
}
function doStuff(q: A | B) {
if ('x' in q) {
// q: A
}
else {
// q: B
}
}
Literal Type Guard
When you have literal types in a union you can check them to discriminate e.g.
type Foo = {
kind: 'foo', // Literal type
foo: number
}
type Bar = {
kind: 'bar', // Literal type
bar: number
}
function doStuff(arg: Foo | Bar) {
if (arg.kind === 'foo') {
console.log(arg.foo); // OK
console.log(arg.bar); // Error!
}
else { // MUST BE Bar!
console.log(arg.foo); // Error!
console.log(arg.bar); // OK
}
}
User Defined Type Guards
JavaScript doesn’t have very rich runtime introspection support built in. When you are using just plain JavaScript Objects (using structural typing to your advantage), you do not even have access to instanceof
or typeof
. For these cases you can create User Defined Type Guard functions. These are just functions that return someArgumentName is SomeType
. Here is an example:
/**
* Just some interfaces
*/
interface Foo {
foo: number;
common: string;
}
interface Bar {
bar: number;
common: string;
}
/**
* User Defined Type Guard!
*/
function isFoo(arg: any): arg is Foo {
return arg.foo !== undefined;
}
/**
* Sample usage of the User Defined Type Guard
*/
function doStuff(arg: Foo | Bar) {
if (isFoo(arg)) {
console.log(arg.foo); // OK
console.log(arg.bar); // Error!
}
else {
console.log(arg.foo); // Error!
console.log(arg.bar); // OK
}
}
doStuff({ foo: 123, common: '123' });
doStuff({ bar: 123, common: '123' });