Types
Types
In Swift, there are two kinds of types: named types and compound types. A named type is a type that can be given a particular name when it’s defined. Named types include classes, structures, enumerations, and protocols. For example, instances of a user-defined class named MyClass
have the type MyClass
. In addition to user-defined named types, the Swift standard library defines many commonly used named types, including those that represent arrays, dictionaries, and optional values.
Data types that are normally considered basic or primitive in other languages—such as types that represent numbers, characters, and strings—are actually named types, defined and implemented in the Swift standard library using structures. Because they’re named types, you can extend their behavior to suit the needs of your program, using an extension declaration, discussed in Extensions and Extension Declaration.
A compound type is a type without a name, defined in the Swift language itself. There are two compound types: function types and tuple types. A compound type may contain named types and other compound types. For instance, the tuple type (Int, (Int, Int))
contains two elements: The first is the named type Int
, and the second is another compound type (Int, Int)
.
You can put parentheses around a named type or a compound type. However, adding parentheses around a type doesn’t have any effect. For example, (Int)
is equivalent to Int
.
This chapter discusses the types defined in the Swift language itself and describes the type inference behavior of Swift.
Grammar of a type
type → array-type
type → dictionary-type
type → function-type
type → type-identifier
type → tuple-type
type → optional-type
type → implicitly-unwrapped-optional-type
type → protocol-composition-type
type → metatype-type
type → Any
type → Self
type → (
type )
Type Annotation
A type annotation explicitly specifies the type of a variable or expression. Type annotations begin with a colon (:
) and end with a type, as the following examples show:
let someTuple: (Double, Double) = (3.14159, 2.71828)
func someFunction(a: Int) { /* ... */ }
In the first example, the expression someTuple
is specified to have the tuple type (Double, Double)
. In the second example, the parameter a
to the function someFunction
is specified to have the type Int
.
Type annotations can contain an optional list of type attributes before the type.
Grammar of a type annotation
type-annotation → :
attributes opt inout
opt type
Type Identifier
A type identifier refers to either a named type or a type alias of a named or compound type.
Most of the time, a type identifier directly refers to a named type with the same name as the identifier. For example, Int
is a type identifier that directly refers to the named type Int
, and the type identifier Dictionary<String, Int>
directly refers to the named type Dictionary<String, Int>
.
There are two cases in which a type identifier doesn’t refer to a type with the same name. In the first case, a type identifier refers to a type alias of a named or compound type. For instance, in the example below, the use of Point
in the type annotation refers to the tuple type (Int, Int)
.
typealias Point = (Int, Int)
let origin: Point = (0, 0)
In the second case, a type identifier uses dot (.
) syntax to refer to named types declared in other modules or nested within other types. For example, the type identifier in the following code references the named type MyType
that is declared in the ExampleModule
module.
var someValue: ExampleModule.MyType
Grammar of a type identifier
type-identifier → type-name generic-argument-clause opt | type-name generic-argument-clause opt .
type-identifier
type-name → identifier
Tuple Type
A tuple type is a comma-separated list of types, enclosed in parentheses.
You can use a tuple type as the return type of a function to enable the function to return a single tuple containing multiple values. You can also name the elements of a tuple type and use those names to refer to the values of the individual elements. An element name consists of an identifier followed immediately by a colon (:). For an example that demonstrates both of these features, see Functions with Multiple Return Values.
When an element of a tuple type has a name, that name is part of the type.
var someTuple = (top: 10, bottom: 12) // someTuple is of type (top: Int, bottom: Int)
someTuple = (top: 4, bottom: 42) // OK: names match
someTuple = (9, 99) // OK: names are inferred
someTuple = (left: 5, right: 5) // Error: names don't match
All tuple types contain two or more types, except for Void
which is a type alias for the empty tuple type, ()
.
Grammar of a tuple type
tuple-type → (
)
| (
tuple-type-element ,
tuple-type-element-list )
tuple-type-element-list → tuple-type-element | tuple-type-element ,
tuple-type-element-list
tuple-type-element → element-name type-annotation | type
element-name → identifier
Function Type
A function type represents the type of a function, method, or closure and consists of a parameter and return type separated by an arrow (->
):
(parameter type) -> return type
The parameter type is comma-separated list of types. Because the return type can be a tuple type, function types support functions and methods that return multiple values.
A parameter of the function type () -> T
(where T
is any type) can apply the autoclosure
attribute to implicitly create a closure at its call sites. This provides a syntactically convenient way to defer the evaluation of an expression without needing to write an explicit closure when you call the function. For an example of an autoclosure function type parameter, see Autoclosures.
A function type can have a variadic parameter in its parameter type. Syntactically, a variadic parameter consists of a base type name followed immediately by three dots (...
), as in Int...
. A variadic parameter is treated as an array that contains elements of the base type name. For instance, the variadic parameter Int...
is treated as [Int]
. For an example that uses a variadic parameter, see Variadic Parameters.
To specify an in-out parameter, prefix the parameter type with the inout
keyword. You can’t mark a variadic parameter or a return type with the inout
keyword. In-out parameters are discussed in In-Out Parameters.
If a function type has only one parameter and that parameter’s type is a tuple type, then the tuple type must be parenthesized when writing the function’s type. For example, ((Int, Int)) -> Void
is the type of a function that takes a single parameter of the tuple type (Int, Int)
and doesn’t return any value. In contrast, without parentheses, (Int, Int) -> Void
is the type of a function that takes two Int
parameters and doesn’t return any value. Likewise, because Void
is a type alias for ()
, the function type (Void) -> Void
is the same as (()) -> ()
—a function that takes a single argument that is an empty tuple. These types are not the same as () -> ()
—a function that takes no arguments.
Argument names in functions and methods are not part of the corresponding function type. For example:
func someFunction(left: Int, right: Int) {}
func anotherFunction(left: Int, right: Int) {}
func functionWithDifferentLabels(top: Int, bottom: Int) {}
var f = someFunction // The type of f is (Int, Int) -> Void, not (left: Int, right: Int) -> Void.
f = anotherFunction // OK
f = functionWithDifferentLabels // OK
func functionWithDifferentArgumentTypes(left: Int, right: String) {}
f = functionWithDifferentArgumentTypes // Error
func functionWithDifferentNumberOfArguments(left: Int, right: Int, top: Int) {}
f = functionWithDifferentNumberOfArguments // Error
Because argument labels are not part of a function’s type, you omit them when writing a function type.
var operation: (lhs: Int, rhs: Int) -> Int // Error
var operation: (_ lhs: Int, _ rhs: Int) -> Int // OK
var operation: (Int, Int) -> Int // OK
If a function type includes more than a single arrow (->
), the function types are grouped from right to left. For example, the function type (Int) -> (Int) -> Int
is understood as (Int) -> ((Int) -> Int)
—that is, a function that takes an Int
and returns another function that takes and returns an Int
.
Function types that can throw an error must be marked with the throws
keyword, and function types that can rethrow an error must be marked with the rethrows
keyword. The throws
keyword is part of a function’s type, and nonthrowing functions are subtypes of throwing functions. As a result, you can use a nonthrowing function in the same places as a throwing one. Throwing and rethrowing functions are described in Throwing Functions and Methods and Rethrowing Functions and Methods.
Restrictions for Nonescaping Closures
A parameter that’s a nonescaping function can’t be stored in a property, variable, or constant of type Any
, because that might allow the value to escape.
A parameter that’s a nonescaping function can’t be passed as an argument to another nonescaping function parameter. This restriction helps Swift perform more of its checks for conflicting access to memory at compile time instead of at runtime. For example:
let external: (() -> Void) -> Void = { _ in () }
func takesTwoFunctions(first: (() -> Void) -> Void, second: (() -> Void) -> Void) {
first { first {} } // Error
second { second {} } // Error
first { second {} } // Error
second { first {} } // Error
first { external {} } // OK
external { first {} } // OK
}
In the code above, both of the parameters to takesTwoFunctions(first:second:)
are functions. Neither parameter is marked @escaping
, so they’re both nonescaping as a result.
The four function calls marked “Error” in the example above cause compiler errors. Because the first
and second
parameters are nonescaping functions, they can’t be passed as arguments to another nonescaping function parameter. In contrast, the two function calls marked “OK” don’t cause a compiler error. These function calls don’t violate the restriction because external
isn’t one of the parameters of takesTwoFunctions(first:second:)
.
If you need to avoid this restriction, mark one of the parameters as escaping, or temporarily convert one of the nonescaping function parameters to an escaping function by using the withoutActuallyEscaping(_:do:)
function. For information about avoiding conflicting access to memory, see Memory Safety.
Grammar of a function type
function-type → attributes opt function-type-argument-clause throws
opt ->
type
function-type → attributes opt function-type-argument-clause rethrows
->
type
function-type-argument-clause → (
)
function-type-argument-clause → (
function-type-argument-list ...
opt )
function-type-argument-list → function-type-argument | function-type-argument ,
function-type-argument-list
function-type-argument → attributes opt inout
opt type | argument-label type-annotation
argument-label → identifier
Array Type
The Swift language provides the following syntactic sugar for the Swift standard library Array<Element>
type:
[type]
In other words, the following two declarations are equivalent:
let someArray: Array<String> = ["Alex", "Brian", "Dave"]
let someArray: [String] = ["Alex", "Brian", "Dave"]
In both cases, the constant someArray
is declared as an array of strings. The elements of an array can be accessed through subscripting by specifying a valid index value in square brackets: someArray[0]
refers to the element at index 0, "Alex"
.
You can create multidimensional arrays by nesting pairs of square brackets, where the name of the base type of the elements is contained in the innermost pair of square brackets. For example, you can create a three-dimensional array of integers using three sets of square brackets:
var array3D: [[[Int]]] = [[[1, 2], [3, 4]], [[5, 6], [7, 8]]]
When accessing the elements in a multidimensional array, the left-most subscript index refers to the element at that index in the outermost array. The next subscript index to the right refers to the element at that index in the array that’s nested one level in. And so on. This means that in the example above, array3D[0]
refers to [[1, 2], [3, 4]]
, array3D[0][1]
refers to [3, 4]
, and array3D[0][1][1]
refers to the value 4.
For a detailed discussion of the Swift standard library Array
type, see Arrays.
Grammar of an array type
array-type → [
type ]
Dictionary Type
The Swift language provides the following syntactic sugar for the Swift standard library Dictionary<Key, Value>
type:
[key type: value type]
In other words, the following two declarations are equivalent:
let someDictionary: [String: Int] = ["Alex": 31, "Paul": 39]
let someDictionary: Dictionary<String, Int> = ["Alex": 31, "Paul": 39]
In both cases, the constant someDictionary
is declared as a dictionary with strings as keys and integers as values.
The values of a dictionary can be accessed through subscripting by specifying the corresponding key in square brackets: someDictionary["Alex"]
refers to the value associated with the key "Alex"
. The subscript returns an optional value of the dictionary’s value type. If the specified key isn’t contained in the dictionary, the subscript returns nil
.
The key type of a dictionary must conform to the Swift standard library Hashable
protocol.
For a detailed discussion of the Swift standard library Dictionary
type, see Dictionaries.
Grammar of a dictionary type
dictionary-type → [
type :
type ]
Optional Type
The Swift language defines the postfix ?
as syntactic sugar for the named type Optional<Wrapped>
, which is defined in the Swift standard library. In other words, the following two declarations are equivalent:
var optionalInteger: Int?
var optionalInteger: Optional<Int>
In both cases, the variable optionalInteger
is declared to have the type of an optional integer. Note that no whitespace may appear between the type and the ?
.
The type Optional<Wrapped>
is an enumeration with two cases, none
and some(Wrapped)
, which are used to represent values that may or may not be present. Any type can be explicitly declared to be (or implicitly converted to) an optional type. If you don’t provide an initial value when you declare an optional variable or property, its value automatically defaults to nil
.
If an instance of an optional type contains a value, you can access that value using the postfix operator !
, as shown below:
optionalInteger = 42
optionalInteger! // 42
Using the !
operator to unwrap an optional that has a value of nil
results in a runtime error.
You can also use optional chaining and optional binding to conditionally perform an operation on an optional expression. If the value is nil
, no operation is performed and therefore no runtime error is produced.
For more information and to see examples that show how to use optional types, see Optionals.
Grammar of an optional type
optional-type → type ?
Implicitly Unwrapped Optional Type
The Swift language defines the postfix !
as syntactic sugar for the named type Optional<Wrapped>
, which is defined in the Swift standard library, with the additional behavior that it’s automatically unwrapped when it’s accessed. If you try to use an implicitly unwrapped optional that has a value of nil
, you’ll get a runtime error. With the exception of the implicit unwrapping behavior, the following two declarations are equivalent:
var implicitlyUnwrappedString: String!
var explicitlyUnwrappedString: Optional<String>
Note that no whitespace may appear between the type and the !
.
Because implicit unwrapping changes the meaning of the declaration that contains that type, optional types that are nested inside a tuple type or a generic type—such as the element types of a dictionary or array—can’t be marked as implicitly unwrapped. For example:
let tupleOfImplicitlyUnwrappedElements: (Int!, Int!) // Error
let implicitlyUnwrappedTuple: (Int, Int)! // OK
let arrayOfImplicitlyUnwrappedElements: [Int!] // Error
let implicitlyUnwrappedArray: [Int]! // OK
Because implicitly unwrapped optionals have the same Optional<Wrapped>
type as optional values, you can use implicitly unwrapped optionals in all the same places in your code that you can use optionals. For instance, you can assign values of implicitly unwrapped optionals to variables, constants, and properties of optionals, and vice versa.
As with optionals, if you don’t provide an initial value when you declare an implicitly unwrapped optional variable or property, its value automatically defaults to nil
.
Use optional chaining to conditionally perform an operation on an implicitly unwrapped optional expression. If the value is nil
, no operation is performed and therefore no runtime error is produced.
For more information about implicitly unwrapped optional types, see Implicitly Unwrapped Optionals.
Grammar of an implicitly unwrapped optional type
implicitly-unwrapped-optional-type → type !
Protocol Composition Type
A protocol composition type defines a type that conforms to each protocol in a list of specified protocols, or a type that is a subclass of a given class and conforms to each protocol in a list of specified protocols. Protocol composition types may be used only when specifying a type in type annotations, in generic parameter clauses, and in generic where
clauses.
Protocol composition types have the following form:
Protocol 1 & Protocol 2
A protocol composition type allows you to specify a value whose type conforms to the requirements of multiple protocols without explicitly defining a new, named protocol that inherits from each protocol you want the type to conform to. For example, you can use the protocol composition type ProtocolA & ProtocolB & ProtocolC
instead of declaring a new protocol that inherits from ProtocolA
, ProtocolB
, and ProtocolC
. Likewise, you can use SuperClass & ProtocolA
instead of declaring a new protocol that is a subclass of SuperClass
and conforms to ProtocolA
.
Each item in a protocol composition list is one of the following; the list can contain at most one class:
The name of a class
The name of a protocol
A type alias whose underlying type is a protocol composition type, a protocol, or a class.
When a protocol composition type contains type aliases, it’s possible for the same protocol to appear more than once in the definitions—duplicates are ignored. For example, the definition of PQR
in the code below is equivalent to P & Q & R
.
typealias PQ = P & Q
typealias PQR = PQ & Q & R
Grammar of a protocol composition type
protocol-composition-type → type-identifier &
protocol-composition-continuation
protocol-composition-continuation → type-identifier | protocol-composition-type
Metatype Type
A metatype type refers to the type of any type, including class types, structure types, enumeration types, and protocol types.
The metatype of a class, structure, or enumeration type is the name of that type followed by .Type
. The metatype of a protocol type—not the concrete type that conforms to the protocol at runtime—is the name of that protocol followed by .Protocol
. For example, the metatype of the class type SomeClass
is SomeClass.Type
and the metatype of the protocol SomeProtocol
is SomeProtocol.Protocol
.
You can use the postfix self
expression to access a type as a value. For example, SomeClass.self
returns SomeClass
itself, not an instance of SomeClass
. And SomeProtocol.self
returns SomeProtocol
itself, not an instance of a type that conforms to SomeProtocol
at runtime. You can call the type(of:)
function with an instance of a type to access that instance’s dynamic, runtime type as a value, as the following example shows:
class SomeBaseClass {
class func printClassName() {
print("SomeBaseClass")
}
}
class SomeSubClass: SomeBaseClass {
override class func printClassName() {
print("SomeSubClass")
}
}
let someInstance: SomeBaseClass = SomeSubClass()
// The compile-time type of someInstance is SomeBaseClass,
// and the runtime type of someInstance is SomeSubClass
type(of: someInstance).printClassName()
// Prints "SomeSubClass"
For more information, see type(of:) [https://developer.apple.com/documentation/swift/2885064-type\] in the Swift standard library.
Use an initializer expression to construct an instance of a type from that type’s metatype value. For class instances, the initializer that’s called must be marked with the required
keyword or the entire class marked with the final
keyword.
class AnotherSubClass: SomeBaseClass {
let string: String
required init(string: String) {
self.string = string
}
override class func printClassName() {
print("AnotherSubClass")
}
}
let metatype: AnotherSubClass.Type = AnotherSubClass.self
let anotherInstance = metatype.init(string: "some string")
Grammar of a metatype type
metatype-type → type .
Type
| type .
Protocol
Type Inheritance Clause
A type inheritance clause is used to specify which class a named type inherits from and which protocols a named type conforms to. A type inheritance clause begins with a colon (:
), followed by a list of type identifiers.
Class types can inherit from a single superclass and conform to any number of protocols. When defining a class, the name of the superclass must appear first in the list of type identifiers, followed by any number of protocols the class must conform to. If the class doesn’t inherit from another class, the list can begin with a protocol instead. For an extended discussion and several examples of class inheritance, see Inheritance.
Other named types can only inherit from or conform to a list of protocols. Protocol types can inherit from any number of other protocols. When a protocol type inherits from other protocols, the set of requirements from those other protocols are aggregated together, and any type that inherits from the current protocol must conform to all of those requirements.
A type inheritance clause in an enumeration definition can be either a list of protocols, or in the case of an enumeration that assigns raw values to its cases, a single, named type that specifies the type of those raw values. For an example of an enumeration definition that uses a type inheritance clause to specify the type of its raw values, see Raw Values.
Grammar of a type inheritance clause
type-inheritance-clause → :
type-inheritance-list
type-inheritance-list → type-identifier | type-identifier ,
type-inheritance-list
Type Inference
Swift uses type inference extensively, allowing you to omit the type or part of the type of many variables and expressions in your code. For example, instead of writing var x: Int = 0
, you can write var x = 0
, omitting the type completely—the compiler correctly infers that x
names a value of type Int
. Similarly, you can omit part of a type when the full type can be inferred from context. For instance, if you write let dict: Dictionary = ["A": 1]
, the compiler infers that dict
has the type Dictionary<String, Int>
.
In both of the examples above, the type information is passed up from the leaves of the expression tree to its root. That is, the type of x
in var x: Int = 0
is inferred by first checking the type of 0
and then passing this type information up to the root (the variable x
).
In Swift, type information can also flow in the opposite direction—from the root down to the leaves. In the following example, for instance, the explicit type annotation (: Float
) on the constant eFloat
causes the numeric literal 2.71828
to have an inferred type of Float
instead of Double
.
let e = 2.71828 // The type of e is inferred to be Double.
let eFloat: Float = 2.71828 // The type of eFloat is Float.
Type inference in Swift operates at the level of a single expression or statement. This means that all of the information needed to infer an omitted type or part of a type in an expression must be accessible from type-checking the expression or one of its subexpressions.